hand,hold,impossible,poker,texas An Amazing Hand Of Poker

An Amazing Hand Of Poker

published by mkone

1 year 3 months 2 weeks ago • 1735 views

tags: hand, hold, impossible, poker, texas

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Comments

****, was just about to post this. beat me to it by 5 friggin' minutes.

-- anyhow, upvote !

written by sirex

| 1 year 3 months 2 weeks ago | CH

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I went out on pocket aces the last time I played. It was really annoying because I was two players away from a sizeable pot.

written by budzos

| 1 year 3 months 2 weeks ago | CH

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Don't you just hate it when that happens?

written by HaricotVert

| 1 year 3 months 2 weeks ago | CH

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Anybody want to figure out the statistics (for 5 different pairs)?

written by Nebosuke | 1 year 3 months 2 weeks ago | CH

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I get close to 1 in 1.5 million.

written by arvana

| 1 year 3 months 2 weeks ago | CH

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You have to check out this hand of poker.
http://www.videosift.com/video/How-to-Lose-Over-300000-in-5-Minutes-Negreanu-VS-Hansen

written by eric3579

| 1 year 3 months 2 weeks ago | CH

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fold pocket kings? ####!

written by ambassdor

| 1 year 3 months 2 weeks ago | CH

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eric3579 asked me how I got those odds, so here it is -- skip if you don't like math!

There are 5 hands. The first card dealt can be anything, but the second through fifth cards all have to be different from the previous cards dealt.

Card 2 would have odds of 48:51 since there are 51 cards left in the deck and three of them can't be dealt to Player 2, as they would have the same face value as Player 1's card.

Cards 3, 4 and 5 would similarly have odds of 44:50, 40:49 and 36:48 respectively.

When Player 1 gets dealt a second card, there are 47 cards left in the deck, and 3 that would match his first card, so his odds of getting a pair are 3:47.

Likewise, Players 2–5 have odds of 3:46, 3:45, 3:44 and 3:43.

Now, multiply all of those odds together to get the odds of 5 different pocket pairs:

48 . 44 . 40 . 36 .  3 .  3 .  3 .  3 .  3  ₌    1   
 51   50   49   48   47   46   45   44   43    1493840

written by arvana

| 1 year 3 months 2 weeks ago | CH

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arent you forgetting the sixth hand that wasnt a pair in that math?

written by JustT1m | 1 year 3 months 2 weeks ago | CH

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Oops, you're right, JustT1m, I didn't notice there were actually six players. That changes things a little! Though the odds would still be in the same ballpark.

written by arvana

| 1 year 3 months 2 weeks ago | CH

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The number of ways for all 5 players to get different pocket pairs is (13 P 5)*((4 C 2)^5). The number of possible hands is (52 C 2)*(50 C 2)*(48 C 2)*(46 C 2)*(44 C 2). Divide the first one by the second one. The probability is 6.69*10^-7, which matches Arvana's answer.

written by jwray

| 1 year 3 months 2 weeks ago | CH

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The 6th hand that we didn't see doesn't change the probabilities. Those cards might as well still be in the deck.

written by jwray

| 1 year 3 months 2 weeks ago | CH

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Thanks, jwray, it's good to be corrected by a real mathematician!

written by arvana

| 1 year 3 months 2 weeks ago | CH

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hmmm... still not sure what happened on the last card there. which hands won and which hands lost?

written by jmd

| 1 year 3 months 2 weeks ago | CH

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The trip Queens won over the pocket pair of Aces.

In other words, the guy with the Aces got shafted.

He played good poker but had bad luck.

written by HaricotVert

| 1 year 3 months 2 weeks ago | CH

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yeah "he played good poker".. this drives me nuts. Wow the guy called with pocket Aces. That is so far from "good poker". It's like holding with A-10 in blackjack.

Anyways, your worst matchup in poker like 2-7 and A-A still means you lose 20% of the time. I fold Aces a lot more than I fold J-10 suited.

written by joedirt

| 1 year 3 months 2 weeks ago | CH

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Someone needs to tell the dealer they need to shuffle the cards after playing Solitare...

written by Payback

| 1 year 3 months 2 weeks ago | CH

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LOL @ solitaire comment. Awesome.

Anyone know the ultimate outcome from this game?

written by Krupo

| 1 year 3 months 2 weeks ago | CH

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lol at solitare

written by sirex

| 1 year 3 months 2 weeks ago | CH

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I fold Aces a lot more than I fold J-10 suited.

You fold aces when now? I really hope you don't mean preflop.

written by rustybrooks | 1 year 3 months 2 weeks ago | CH

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I've folded aces preflop a few times but only in satellites where the top X moves on, it was close to the "money" and I was safe to move forward, and a big stack had made a significant raise before me. In that situation there is no reason to risk my stack on someone not sucking out. Aces aren't a sure thing.

written by T-man

| 1 year 3 months 2 weeks ago | CH

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But what are the odds of three of those pocket pairs being AA, KK, and QQ?

written by T-man

| 1 year 3 months 2 weeks ago | CH

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OK, sure, I understand that. So, would you call with JTs there? Course not.

written by rustybrooks | 1 year 3 months 2 weeks ago | CH

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No way. You are right. In aggregate, I fold J-10 suited much more than I do aces - preflop and postflop.

written by T-man

| 1 year 3 months 2 weeks ago | CH

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Arvana, your odds are accurate for a table with 5 players. But there were 6 players, and thus, 6 different ways to make 5 pairs -- only 5 of the 6 cards had to hit the second time around. I think you divide your number by 6 to get the right odds, but I wouldn't hang my name on that.

written by messenger

| 1 year 3 months 2 weeks ago | CH

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